Solving complex linear equations | Maths | Quizalize & Oak National Academy

Starter quiz

$1\over7$ is the ______ of $7$

fraction

division

reciprocal ✓

divisor

multiplier
Solve $6x+9=27$

$x=3$ ✓

$x=6$

$x=9$

$x=18$
Solve ${x\over3}=15$

$x=45$ ✓

$x=18$

$x=5$

$x={1\over5}$
Calculate ${2\over3}\times{4\over5}$

$6\over15$

$6\over20$

$8\over15$ ✓

$10\over12$

$12\over10$
Which of these expressions are equivalent to ${{x+1}\over3}\times{2\over3}$ ?

${2x+1}\over9$

${2{(x+1)}\over9}$ ✓

${2{(x+1)}\over3}$

${2x+2}\over3$

${2x+2}\over9$ ✓
Expand and simplify $8({{x}\over8})$

$8$

$x$ ✓

$8x$

${{8x}\over8}$

$x=8$

${{56}\over{y}}=7$ is an example of a ______ equation.

variable

rational ✓

irrational

special
The solution to ${{6x−2}\over{4}}=7$ is $x=$ ______

'5' ✓
Solve ${{2x}\over{3}}+1=11$

$x=15$ ✓

$x=16$

$x=17$

$x=18$
Which is the most efficient first step when solving the equation ${{x+7}\over{9}}={{x-1}\over{3}}$ ?

Subtract $7$ from both sides.

Add $1$ to both sides.

Multiply both sides by $9$ ✓

Multiply both sides by $3$

Multiply both sides by $27$
Solve ${{x+7}\over{9}}={{x−1}\over{3}}$ . The solution is $x=$ ______

'5' ✓
Solve ${{32}\over{3x}}=8$

$x={3\over4}$

$x=3$

$x=4$

$x={4\over3}$ ✓

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Any linear equation written in the form Ax + B = C can be solved.
Equations involving division by a constant can be manipulated to reach the form Ax + B = C.
Equations involving division by a variable can be manipulated to reach the form Ax + B = C.

Pupils often \"multiply through by $5$ \" and turn ${{2x+1}\\over5}={10}$ into ${{10x+5}}={50}$

Use equivalent fractions as opposed to multiplying through. In one simple step ${{2x+1}\\over5}={10}$ becomes ${{2x+1}\\over5}={50\\over5}$

Equation - An equation is used to show two expressions that are equal to each other.