Starter quiz
- This quadrilateral is a kite. Find the value of angle , in degrees.
- '100' ✓
- This diagram shows an accurate construction of a perpendicular bisector. YZ has a length of 8.4 cm. Which of these is the smallest value of that can be used in this construction?
- 2.1 cm
- 4.3 cm ✓
- 8.4 cm
- 16.8 cm
- 8.4 cm
-
- Match the sentence to the diagram.
- a⇔A bisector to line segment QV ✓
- b⇔A perpendicular to line segment QV ✓
- c⇔A perpendicular bisector to line segment QV ✓
- d⇔An intersecting line to line segment QV ✓
- This is an incomplete construction to find the perpendicular bisector of YZ. Which of these steps is missing from this construction?
- A circle with centre at point Y.
- A line segment connecting the intersection to point Z.
- An arc below YZ with centre at point Z. ✓
- An arc above YZ with centre at point Z.
- A line through two pairs of intersecting arcs. ✓
-
- This is an accurate construction to draw a rhombus. What is the perimeter (in cm) of the rhombus that can be drawn from this construction?
- '56' ✓
- Sofia starts her construction of a perpendicular bisector to EF. She is about to move the pair of compoasses to construct a second circle. Which of these statements are true?
- Sofia needs to place the compass needle at the midpoint of EF.
- Sofia should draw a circle with centre at the intersection of EF and the circle.
- Sofia needs to draw an arc with centre at point F next.
- Sofia should adjust the compass width so that both circles drawn are congruent. ✓
- Currently, the next circle Sofia draws will be smaller than the first. ✓
-
Exit quiz
- The line segment EF has been shortened by constructing a circle of radius 8 cm, with a centre at point K. What is the length (in cm) of the shortened line segment?
- '16' ✓
- Which of these diagrams shows the most appropriate first step when constructing the perpendicular to line segment TU through point Z?
- a
- b
- c
- d ✓
-
- Izzy has shortened line segment LM by drawing a circle with centre at point Z. Izzy wants to draw four arcs of radius cm to construct a perpendicular. What value must be greater than?
- 4 cm
- 6 cm
- 12 cm ✓
- 14 cm
- 28 cm
-
- A line segment is extended so that a perpendicular can be constructed through point Z. Which of these diagrams shows a suitable extension of the line segment?
- a
- b ✓
- c
- d
-
- Which of these four circles can help in the construction of the perpendicular to line segment WU through point Z?
- a
- b ✓
- c ✓
- d
-
- Match the values to their statements.
- 14 cm⇔the shortest distance from X to an extension of JK ✓
- 15 cm⇔the shortest distance from X to line segment JK ✓
- 17 cm⇔the radius of circle with centre at point X ✓
- 28 cm⇔the shortest distance from X to point J ✓
Worksheet
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Presentation
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Lesson Details
Key learning points
- A rhombus can be constructed from two congruent isosceles triangles.
- This can be used to construct a perpendicular to a line through a point.
- This perpendicular has special properties that can be investigated.
- Shortest distances can be found using constructions with perpendicular lines.
Common misconception
You can't accurately draw the perpendicular to a point on a line segment close to its endpoint.
The perpendicular to a line segment through any point can be found; some line segments just require extending in length first.
Keywords
Bisect - To bisect means to cut or divide an object into two equal parts.
Rhombus - A rhombus is a parallelogram where all sides are the same length.
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